Piecewise Function, Proving continunity

1. The problem statement, all variables and given/known data
[PLAIN]http://www.freemathhelp.com/forum/download/file.php?id=1610 [Broken]

3. The attempt at a solution
[PLAIN]http://img651.imageshack.us/img651/9817/snapshot201010119.jpg [Broken]

This is what I have so far.
I am not sure about the pattern between the x interval [0,1]
I know there is something weird going on in between there.

I know that the function is not continious between x=0 and x=1, but I can't figure out the pattern.
I know 1/3,1/4,/1,5... all lie under x=1.
But if the denominator is not a natural number it is simply squared.
for example;

if x=1/2.5
then f(x) = (1/2.5)^2

there must be a value for x which makes it discontinous.
PLEASE HELP :(
and please point out any where I went wrong!
 
Last edited by a moderator:

Want to reply to this thread?

"Piecewise Function, Proving continunity" You must log in or register to reply here.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Latest threads

Top