- #1
MrBailey
- 19
- 0
Hi from a newbie.
I have an apparently simple problem, but could use some guidance on how to do it.
I have the following function:
[tex]F(x)=\int^{x}_{0}f(t)dt,\ 0\leq x\leq3[/tex]
where [tex]f(x)=\left\{\begin{array}{lll}1,&\mbox{ if }0\leq x<1\\2-x,&\mbox{ if }1\leq x<2\\0,&\mbox{ if }2\leq x\leq 3\end{array}\right[/tex]
Is it as simple as:
[tex]F(x)=\left\{\begin{array}{lll}x,&\mbox{ if }0\leq x<1\\2x-\frac{x^2}{2},&\mbox{ if }1\leq x<2\\0,&\mbox{ if }2\leq x\leq 3\end{array}\right[/tex]
A plot of F(x) for the interval would show discontinuities at x=1 and x=2.
Thanks for your help.
Bailey
I have an apparently simple problem, but could use some guidance on how to do it.
I have the following function:
[tex]F(x)=\int^{x}_{0}f(t)dt,\ 0\leq x\leq3[/tex]
where [tex]f(x)=\left\{\begin{array}{lll}1,&\mbox{ if }0\leq x<1\\2-x,&\mbox{ if }1\leq x<2\\0,&\mbox{ if }2\leq x\leq 3\end{array}\right[/tex]
Is it as simple as:
[tex]F(x)=\left\{\begin{array}{lll}x,&\mbox{ if }0\leq x<1\\2x-\frac{x^2}{2},&\mbox{ if }1\leq x<2\\0,&\mbox{ if }2\leq x\leq 3\end{array}\right[/tex]
A plot of F(x) for the interval would show discontinuities at x=1 and x=2.
Thanks for your help.
Bailey