- #1

- 7

- 0

[sum]Fx=ma=mgsin [the] -[mu]mgcos[the] I canceled out the mass on both sides and get

[sum]Fx=a=gsin [the] -[mu]gcos[the]

For the y forces I have

[sum]y=N=mgcos[the]

As far as the difference in the time with or with out friction I have x=mgsin[the]=(1/2)a[tex]t^2[/tex] for the slide with no friction and I have x=mgsin[the]=2a[tex]t^2[/tex]for the slide with friction

This is all the info I have been able to come up with...I can't figure out how to put it all together. Thanks for helping. I've been working on this one for awhile.