Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Pion Annihilation

  1. Feb 14, 2010 #1
    I'm running into a dilemma:

    I've recently worked out the Feynman rules for Chiral perturbation theory for 2 flavors, and discovered that the term

    [tex]\mathcal{L}=\frac{f_\pi^2}{4} \Tr[(D_\mu U)^\dag (D^\mu U)][/tex]​

    seems to contain the term [itex]~ e^2 A_\mu A^\mu \pi^0 \,\pi^0[/itex] describing a direct interaction of two photons with two neutral pions. This is weird since the neutral pions don't carry electric charge to which photons can couple.

    This term would allow the two neutral pions to annihilate into two photons. Can that happen, or did I make a mistake in computing the Feynman rules? Also, is there a reference containing all the Feynman rules for Chiral perturbation theory?
     
  2. jcsd
  3. Feb 15, 2010 #2

    Meir Achuz

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Pions have no charge but they do have a charge form factor due to their quark structure.
    pi0 + pi0 --> 2 photons is conceivable, but extremely unlikely.
    Of course, a single pi0 decays to two photons via its electromagnetic interaction.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Pion Annihilation
  1. Spin of the pion (Replies: 2)

  2. Pion decays (Replies: 2)

  3. Pion decay (Replies: 5)

  4. Neutral pions (Replies: 2)

Loading...