- #1
Cyrus
- 3,238
- 16
This came up in the homework help section, and has me scratching my head.
Consider a vertical pipe open to atm at one end under steady flow.
The velocity in has to be equal to the velocity out because of the cont. equation.
The pressure at the bottom is zero, (atm), and the datum is at the bottom, (z=0).
That only leaves,
[tex] P + \gamma h = 0 [/tex]
h can't be negative, so that means the pressure must be equal and opposite to the hydrostatic head.
But then that mean's the fluid will flow in the direction of increasing pressure because the pressure will become less negative as you move down ?? <enter confusion>
Show me what I did wrong.
Consider a vertical pipe open to atm at one end under steady flow.
The velocity in has to be equal to the velocity out because of the cont. equation.
The pressure at the bottom is zero, (atm), and the datum is at the bottom, (z=0).
That only leaves,
[tex] P + \gamma h = 0 [/tex]
h can't be negative, so that means the pressure must be equal and opposite to the hydrostatic head.
But then that mean's the fluid will flow in the direction of increasing pressure because the pressure will become less negative as you move down ?? <enter confusion>
Show me what I did wrong.