1. The problem statement, all variables and given/known data The following image shows the parts A and B of a pipe where the middle part goes under a hill the length of both parts A and B is 30m and the diameter of them each is 2cm where as the middle part has a length of 110m to determine the middle part's diameter one engineer decided to push water in the pipe with a speed of 2.50 m\s in part A he dropped a small coin in the flow and noticed that it took 88.8 seconds for it to start from A and exit from B. 1)calculate the diameter of the middle pipe 2. Relevant equations v=d\s A1*v1=A2*v2. (Continuity equation) A=pi*r^2 3. The attempt at a solution Finding the area of a and b: 0.02^2*pi=0.00125m^2 Finding the time it would take to travel through A and B (not including mid pipe) 2.50=30/s s=12 So for a and b it would take 24 seconds For mid part it would take 88.8-24=64.8 Mid part speed 110/64.8=1.697m\s So 0.00125*2.50=1.697*A2 Area=0.001841 0.0018141=pi*r^2 R=0.024m Answer sheet says that the diameter is 3.60cm help!