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Pitch calculation is always doubled

  1. Sep 30, 2012 #1
    1. The problem statement, all variables and given/known data
    A 945N resistance force is overcome with a 13.5N effort using a screwdriver whose handle is 24mm in diameter. What is the pitch of the screw?


    2. Relevant equations
    Given:
    r = 24mm
    FE = 13.5N
    FR = 945N
    Pitch = ?

    r is radius
    FE is force effort
    FR is resistance force
    Pitch is unknown spacing of screw

    Basic equation:
    FR * pitch = FE * 2pi * r




    3. The attempt at a solution
    Working equation
    Pitch = (FE * 2pi * r) / FR

    Substitution
    Pitch = (13.5N * 2pi * 24mm) / 945N

    Pitch = 2.154mm yet the answer is said to be 1.08mm which is exactly half of my initial answer. Is there something I am missing?
     
  2. jcsd
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