Two small pith balls, each of mass m = 12 g, are suspended by 1.2 m fine strings and are not moving. If the angle that each string makes with the vertical is q = 42.6 , and the charges on the two balls are equal, what is that charge (in microC)? I equated the forces in x and y to zero: Tcos42.6-117.6=0 T=159.76 Tsin42.6+Fe=0 plugging in 159.76 Fe=108 then i used the equation Fe=kQ^2/r^2 i solved for r by doing this: r=2(1.2sin42.6) r=1.6 m I'm not sure if my steps are right. Can someone help me? Thanks in advance!