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PIV full-wave Bridge Rectifier
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[QUOTE="SuperCat, post: 5506099, member: 586138"] [h2]Homework Statement [/h2] Part C of the problem below. I have the solution but I don't follow the logic. [ATTACH=full]188724[/ATTACH] [ATTACH=full]188725[/ATTACH][h2]Homework Equations[/h2] Turns ratio: Vp/Vs = Np / Ns KVL I do not think I need any elaborate formulas to solve this. [h2]The Attempt at a Solution[/h2] Solution Provided by instructor: [ATTACH=full]188726[/ATTACH] I am confused why there is 2 in front of Vs. When I apply KVL to a loop it looks something like: Reverse Biased Diode = Forward Biased Diode + Vo My KVL matches up with page 213 of Microelectronics Circuits Sedra 7e: [ATTACH=full]188727[/ATTACH] The solution provided to me seems like it would match up with a center-tapped full-wave rectifier, but I have asked a handful of classmates who all seem to agree with the provided solution so I was hoping to either receive confirmation that the solution provided to me is wrong or an elaboration. Many thanks! [/QUOTE]
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