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A uniform rod of length 1.15 m is attached to a frictionless pivot at one end. It is released from rest from an angle of 27 degrees above the horizontal. Find the magnitude of the initial acceleration of the rod's center of mass.

So far I've only been able to figure out that I have to use Newton's Second Law of rotation, F x r = I x alpha. How do i derive that to figure out acceleration? Do i break down F into ma, and cancel the m's on each side that result from inertia?

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# Homework Help: Pivoting Rod

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