1. The problem statement, all variables and given/known data A uniform rod is pivoted at its center and a small weight of mass M = 5.07 kg is rigidly attached to one end. You may neglect the size of the weight and assume it is located right at the end of the rod. 2. Relevant equations Now suppose that the rod has length L = 5.4 m and mass mrod = 10.1 kg. Suppose also that there are no external forces applied (i.e. Fh = Fv = 0). The system is released from rest at the q = 37° angle. What is the angular acceleration just after it is released? angular acceleration:1.7437 rad/s^2 What is the angular velocity when the rod is vertical? 3. The attempt at a solution mgh=.5Iw^2 where h=sin 53*L/2=2.156 w=sqrt(2mgh/I) this is not the correct answer. Can somebody help me. I dont know what im doing wrong.