The problem statement, all variables and given/known data[/b] A sledgehammer with a mass of 2.30 kg is connected to a frictionless pivot at the tip of its handle. The distance from the pivot to the center of mass is r_cm=0.570 m, and the moment of inertia about the center of mass is I_cm = 0.0390 kgm2. If the hammer is released from rest at an angle of theta=40.0 degrees such that H=0.366 m, what is the speed of the center of mass when it passes through horizontal? The diagram is attached. 3. The attempt at a solution My prof did a similar question during class with energy, and so that's the way I tried to solve it. With this incorrect, I honestly don't know how else to go about this problem. E1 = E2 mgH = (1/2)Iw^2 2mgH/I = w^2 w = √(2mgH/I) w = 20.568 rad/s *Because the question asks for speed, I tried this as the answer and the units were rejected. So I tried to solve for velocity instead. mgH = (1/2)I(v^2/r^2) v^2 = 2mgHr^2/I v = √(2mgHr^2/I) v = 19.37 m/s Again, incorrect. Does anyone know how to help? I would genuinely appreciate it. I've got a final coming up and not knowing how to go about this problem, or even what specifically to solve for when asked for 'speed', is really making me panic.