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Niobium Nb has the BCC crystal with a lattice parameter of a= .3294 nm

Find the planar concentrations of atoms per m^2 of the (100, (110) and (111) planes.

The 100 plane has 1 atom on the plane (1/4 times 4)

the 110 plane has 2 atoms on the plane and using pythagorean theorem the long side is a*sqrt(2)

http://www.gly.uga.edu/schroeder/geol6550/111.jpeg [Broken]

best pic I could find for the 111 plane

Now for the last plane (111) this is what I did

the area would be 1/2 base * height

the base is [tex]a*\sqrt2[/tex] and

pythagorean theorem to find the height is a^2 and half of the long side from plane (110) squared [tex]\sqrt{a^2+\frac{2a^2}4}=.4034nm[/tex]

[tex]

\frac12(.4034)10^{-9}(.3294)10^{-9}

[/tex]

Now how many atoms are on the plane? and are there mistakes in what I have done so far?

And how many atoms would that (111) plane have in a FCC model?

Answer would have number of atoms over area

Thanks for the help

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# Homework Help: Planar concentration

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