Planck scale dimensions

  • Thread starter Orion1
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  • #1
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Main Question or Discussion Point


Planck energy:
[tex]E_P = m_P c^2 = \sqrt{\frac{\hbar c^5}{G}}[/tex]

Gravitational radius:
[tex]r_G = \frac{r_s}{2} = \frac{G m_P}{c^2}[/tex]

Gravitational radius is equivalent to Compton wavelength:
[tex]r_G = \overline{\lambda}_C[/tex]

[tex]\frac{G m_P}{c^2} = \frac{\hbar}{m_P c}[/tex]

Planck force is a constant in the Einstein field equation:
[tex]F_P = \frac{E_P}{r_G} = m_P c^2 \left( \frac{c^2}{G m_P} \right) = \frac{c^4}{G} = \frac{8 \pi T_{\mu \nu}}{G_{\mu\nu}}[/tex]

The maximum ratio of energy per gravitational length:
[tex]\boxed{\frac{c^4}{G} = \frac{8 \pi T_{\mu \nu}}{G_{\mu\nu}}}[/tex]

Are Planck scale dimensions the maximum limits in the Universe?

Reference:
http://en.wikipedia.org/wiki/Planck_force" [Broken]
http://en.wikipedia.org/wiki/Planck_mass" [Broken]
http://en.wikipedia.org/wiki/Planck_energy" [Broken]
 
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  • #2
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Where did you get that expression for the quotient of the Stress-enery-tensor and the Einstein-tensor from? As far as I know, it's not valid to divide two tensor-valued quantities.
 
  • #3
970
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Where did you get that expression for the quotient of the Stress-enery-tensor and the Einstein-tensor from?
From Einstein's field equation:
[tex]G_{\mu \nu} = \frac{8 \pi G}{c^4} T_{\mu \nu}[/tex]

As far as I know, it's not valid to divide two tensor-valued quantities.
It is not possible to divide tensors. However, It is possible to divide the solutions after the tensors have been solved for a specific solution.

For example:
[tex]\boxed{\frac{c^4}{G} = \frac{8 \pi T_{r r}}{G_{r r}}} \; \; \; \mu = \nu[/tex]

Are Planck scale dimensions the maximum limits in the Universe?
 
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