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## Homework Statement

A plane traffic monitor monitors traffic on a major highway in the U.S. by flying around 1500m above the road with a constant speed of 200 Km / h. Using the radar, the pilot discovers a car thought to be traveling above the speed limit and is located 2400m from the plane and in order for the plane to stand directly above the car, itneeds to reduce its speed at a rate of 220Km/h^2. Calculate the speed of the car.

## Homework Equations

We can calculate the distance between the car and the plane using the Pythagorean Theorem, that gives us that the distance is 1,87km.

The plane will travel x distance while catching up to the speed of the car and [tex]x=u_p t - 1/2 a t^2 , where a = 220 km/h^2 [/tex]

The car will travela distance x+x' in the same time (at a constant speed let's say) that is [tex]x+x'=u_c t[/tex] where x'=1,5 km

We substitute t from the second equation and get the equation below :

[tex]x = u_p \frac{x+x'}{u_c} - \frac{a(x+x')^2}{2(u_c)^2}[/tex]

## The Attempt at a Solution

As I state before, this is my approach to the problem. It is pretty straightforward, but I feel I'm missing something, since I don't know the distance x . I can't find the clue in the problem statement, and I am stuck trying to figure it out. Any suggestions?

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