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Plane flying

  1. Jan 30, 2008 #1
    1. The problem statement, all variables and given/known data

    A plane passes from 900 meters over my head. I hear the shockwave after 2.2 seconds. At what speed in Mach is the plane flying ? Speed of sound = 331. 4 m/s

    2. Relevant equations

    Machs = speed of plane / speed of sound

    3. The attempt at a solution

    I dont have any clue where to go with this, maybe find the angle of the cone ? it gave me an angle of like .14 degrees and an impossible answer of the plane speed.... dah

    Thanks in advance
     
  2. jcsd
  3. Jan 30, 2008 #2

    Dick

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    Call the mach ratio m. From this you know the horizontal distance the plane has traveled since it was overhead (in terms of m) since you know t=2.2sec. That lets you write down an expression for the cone angle in terms of the sides of the right triangle you just drew. You did draw it, right? Now you also know an expression for the angle of the mach cone in terms of m, I'm sure. Equate the two angles and solve for m.
     
  4. Jan 31, 2008 #3
    do you mean tan(angle) = 2.2/900 ???
     
  5. Jan 31, 2008 #4
    i made a drawing
     

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  6. Jan 31, 2008 #5

    Dick

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    No. 2.2 has the dimensions of sec. 900 has dimensions of meters. The argument of tan is dimensionless. You want a ratio of velocities, tan(angle)=vs/(m*vs) where vs is the velocity of sound. Or just 1/m. Don't you have that written down someplace? I was wondering where you got 0.14 degrees.
     
    Last edited: Jan 31, 2008
  7. Jan 31, 2008 #6
    nah we've been threw this section so fast, only thing i have is

    vs = c / sin(angle)

    and
    machs = vs/c = 1 / sin(angle)


    where vs is velocity of thing moving, c is velocity of sound
     
    Last edited: Jan 31, 2008
  8. Jan 31, 2008 #7
    How do i find the angle, thats the question :/
     
  9. Jan 31, 2008 #8

    Dick

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    I don't know where that is coming from. Not surprising, since I haven't a clue as to what 'c' is supposed to mean. I think you may need a better reference than just your notes or you will just need to use physical common sense.
     
  10. Jan 31, 2008 #9
    I mentionned in my post, c is the velocity of sound, in this problem we use c = 331.4

    Plane is at 900 meters above my head and i hear the sound after 2.2 seconds, thats all i got.
     
  11. Jan 31, 2008 #10

    Dick

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    You need to write down two equations in the mach number m and solve them simultaneously. I wish I could hang around and help, but it's late here and I've got to go. Hopefully somebody else can pick this up.
     
  12. Jan 31, 2008 #11
    thanks for the help !
     
  13. Jan 31, 2008 #12

    Dick

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    Ok. I don't think you mentioned that in your post. So vs is speed of the source? sin(angle) is not the right trig function. If vs=c then the cone angle should be 45 degrees. Write tan(angle) instead. Still gotta go. Sorry.
     
  14. Jan 31, 2008 #13

    Dick

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    Ok again, I feel guilty. tan(angle)=1/m. From the picture you drew, write down another expression for tan(angle) in terms of the sides of the geometric triangle. The hypotenuse distance is c*t. The vertical distance is 900m. What's another expression for tan(angle)?
     
    Last edited: Jan 31, 2008
  15. Jan 31, 2008 #14
    HEY MAN, i think i finally got it:

    first equation - nb of machs :

    machs = velocity of plane / velocity of sound

    second - distance ratio:

    tan(angle) = x/900

    third:

    velocity of plane / velocity of sound = 1/sin(angle)

    fourth:

    x = velocity of plane * 2.2 secondes

    x is the distance travelled by the plane
    angle is the angle formed by the triangle of distances
    machs is the nb of machs
    and velocity of plane !

    4 equations - 4 variables !


    w00t

    VELOCITY OF SOUND = 331.4
     
  16. Jan 31, 2008 #15
    thanks anyway man.

    youve been great !

    good night :D
     
  17. Jan 31, 2008 #16

    Dick

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    Maybe. I'm not quite following you. Zzzzz. You're welcome and good night to you.
     
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