- #1

IsaacCB

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- 0

## Homework Statement

The uniform 3.6m pole is hinged to the truck bed and is released from the vertical position as the truck starts from rest with an acceleration of 0.9m/s^2. If the acceleration remains constant during the motion of the pole as it reaches the horizontal position what is the angular velocity of the pole as it reaches the horizontal position.

## Homework Equations

a(tangential)=mrθ''

a(normal) = mrω^2

ƩMo=Iθ''+Ʃma(vector)d

I=k^2m

## The Attempt at a Solution

Using the given formula ƩMo=Iθ''+Ʃma(vector)d to find θ''.

so 0= Iθ''+mrθ''+mg1.8sin(θ)-ma*1.8cos(θ)

haven't been able to get past this point