Planet is 2.00 a.u. when closest to sun. eccentricty is .500. find period

In summary, the conversation is discussing the calculation of the period of a planet with a semi-major axis of 2.00 a.u. and an eccentricity of .5000. The conversation includes the application of Kepler's 3rd law, which states that the period (in years) is directly proportional to the semi-major axis (a) cubed. The final calculation for the period is T = 8 years.
  • #1
c-murda
67
0

Homework Statement



a planet is 2.00 a.u. when it is closest to the sun. its eccentricity is .5000. Find its period in years.

Homework Equations





The Attempt at a Solution



i got this so far... don't know if it is right

PD + AD = A
-AD - PD = F <SUBTRACTING THESE TWO>

2PD = A - F
2PD = A - (EA)
2PD = A(1-E)
2PD/(1-E) = A

A = 2(2)/(1.-.5)
A= 8 a.u.

then for a

a= 8.00/2
a= 4.00 a.u.

T^2 = a^3

T = sqrt(a^3)
T = 8

im lost T = 8 what? years?
 
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  • #2
kepler's 3rd law says Period( in years) is directly proportional to semi axis (a) cubed. correct?

so was that last line:

T^2 = a^3

correct?
 
  • #3
anyone i got a 7 15 dead line
 

1. What is the meaning of "a.u." in this context?

The abbreviation "a.u." stands for "astronomical unit" and is a unit of measurement used to describe distances in the solar system. 1 a.u. is equal to the average distance between the Earth and the Sun, which is about 93 million miles.

2. How do you calculate the period of a planet with a given eccentricity and distance from the sun?

The formula for calculating the period (P) of a planet with a given eccentricity (e) and distance from the sun (a) is P = (2π√(a^3))/√(1-e^2), where a is measured in a.u. and e is unitless. In this case, the period would be P = (2π√(2^3))/√(1-0.5^2) = 3.82 years.

3. How does eccentricity affect a planet's orbit around the sun?

Eccentricity refers to the shape of a planet's orbit, with a value of 0 representing a perfectly circular orbit and a value of 1 representing a highly elliptical orbit. The higher the eccentricity, the more elongated and less predictable the orbit becomes. In this case, the planet's orbit would be more elongated and take longer to complete one full revolution around the sun compared to a planet with a lower eccentricity.

4. Is there a relationship between a planet's period and its distance from the sun?

Yes, there is a direct relationship between a planet's period and its distance from the sun. The farther a planet is from the sun, the longer its period will be. This can be seen in Kepler's third law, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.

5. How does a planet's eccentricity change over time?

A planet's eccentricity can change over time due to various factors, such as gravitational interactions with other planets or external forces like comets or asteroids. However, these changes are usually very small and occur over long periods of time, so for practical purposes, the eccentricity of a planet can be considered constant.

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