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Homework Help: Plate Capacitor

  1. Feb 16, 2010 #1
    A parallel plate capacitor of capacitance 10microfarads has the space between filled with material with
    (dielectric constant k)= 4.0. The capacitor is charged to a potential difference of 2.0V . With the capacitor connected
    to the battery the dielectric is removed.
    1. The capacitance is F.
    2. The potential difference across the capacitor is V .
    3. The charge on the plates is C.
    4. The energy stored in the capacitor is J.

    F=C/V
    [tex]\kappa[/tex]= E[tex]_{}[/tex]/E

    I dont get what this is asking for or how to carry it out
     
  2. jcsd
  3. Feb 16, 2010 #2
    I don't see a question. You seem to have included some weird latex codes that only produce a
    large grey square while trying to write [tex] k = \frac {\epsilon} { \epsilon_0} [/tex]
     
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