1. The problem statement, all variables and given/known data Find the general solution of y'+ay=0. 2. Relevant equations dy/dx=-ay dy/y=-a dx ∫ dy/y=∫ -a dx ln(y)=-ax+C y=e^(-ax) 3. The attempt at a solution What I want to know is that is y=e^(-ax) the answer or y=ce^(-ax) is the answer?