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f(x)=(x^(2)+5x+2)^(4)
f'(x)= 4(x^2 + 5x + 2)^3 (2x + 5)
= 8x + 20(x^2 + 5x + 2)^3
is this right
than my equation of the tangent turned out to be y=160x +16
f'(x)= 4(x^2 + 5x + 2)^3 (2x + 5)
= 8x + 20(x^2 + 5x + 2)^3
is this right
than my equation of the tangent turned out to be y=160x +16