I don't understand why that is correct.

  • Thread starter rejz55
  • Start date
In summary, the volume of a right circular cylinder with a length of 2.3±0.1 and radius of 0.12±0.05m can be calculated using the formula V=πr^2h, where r is the radius and h is the length. To account for uncertainty, we use the propagation of uncertainty formula, resulting in a volume of 0.104049±0.129383m^3. However, another method involves distributing pi to the uncertainty, which gives a slightly different answer of 0.10430±0.09123m^3.
  • #1
rejz55
19
0
[SOLVED] Please check

Homework Statement


Find the volume of a right circular cylinder with a measured length of 2.3±0.1 and radius 0.12±0.05m.


Homework Equations



Propagation of uncertainty Multiplication: (a±uncertaitya) (b±uncertaintyb)= ab± ab[(uncertaintya/a) + (uncertaintyb / b)

Power: (a±Uncertaintya)^n = a^n ± na^n-1 (uncertaintya)

The Attempt at a Solution


radius^2= 0.12^2 ± 2*(.12^1)*0.05
= 0.0144±0.012

=(0.0144)(2.3)(Pi) ± (0.0144) (2.3) (pi) [(0.1/2.3)+(0.0144/0.012)
= .104049 ± .129383

My friend told me her answer is .10430±0.09123..she said she distributed the pi to the uncertainty..
 
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  • #2
rejz55 said:

The Attempt at a Solution


radius^2= 0.12^2 ± 2*(.12^1)*0.05
= 0.0144±0.012

=(0.0144)(2.3)(Pi) ± (0.0144) (2.3) (pi) [(0.1/2.3)+(0.0144/0.012)

you exchanged 0.0144 and 0.012 here.
 
  • #3
y not? its the new value of the radius cause the radius should be squared..thanks..
 
  • #4
I got it right now..Thanks
 

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