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Precalculus Mathematics Homework Help
Please explain the proofs for sin(90 - θ)
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[QUOTE="jayanthd, post: 4520843, member: 481878"] He is proving with the top four figures that sin(90 - θ ) = cos(θ). It is from the book "Theory and Problems of Plane and Spherical Trigonometry by Frank Ayres, Schaum's Outline Series" The book is available here. http://archive.org/details/SchaumsTheoryProblemsOfTrigonometry Please explain the proofs in page nos 56 and 57. In the 2nd figure from top ∠AOP = (180 - θ). How does he say ∠BOP1 = (90 - θ)? and ∠OAP and ∠OBP1 = 90. [ATTACH=full]164336[/ATTACH] [/QUOTE]
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Precalculus Mathematics Homework Help
Please explain the proofs for sin(90 - θ)
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