## Homework Statement

4^x + 6(4^-x) = 5

## Homework Equations

log??? since this is the unit we are doing, but i'm not sure if it applies.

## The Attempt at a Solution

I was thinking of changing 4^x to a variable like 'a', but 4^-x is not the same so I can't replace that with 'a' as well.
Then I though 4^-x = 1/4 ^x
So
4^x + 6[(1/4)^x] = 5

and I'm lost.
thanks :)

Simon Bridge
Homework Helper
You have:

$$4^{x}+6(4^{-x})=5$$ ... is that right?

... and you want to put it into some form that you can integrate or differentiate or something?
You suspect it has something to do with taking a logarithm - so do I :), since ##\log_4(4^x)=x## hugely simplifies the problem.

Your intuition to put ##a=4^x## is a good one - with that substitution you get:
$$a+\frac{6}{a}=5$$ ... which is hard to think about, so put it in standard form.
Hint: multiply both sides by ##a##.
What sort of equation is that?

Last edited:
1 person
it is actually,

4^x + 6(1/4)^x = 5