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The1BigJones
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This is my first posting on the site. I read the directions, I hope I follow all applicable rules. In advance, thank you for your help.
Find indefinite integral:
Variables (X)
Problem:
[tex]\int[/tex]Csc2(eCot(X))DX
None:
U=eCot(X)
DU=eCot(X) * -Csc2(X)
Pyth Iden Csc2(X)=1 + Tan2(X)
I keep going back to:
[tex]\int[/tex][Csc2(Something)]=-Cot(Something) I just can't figure out the relation.
Find indef. Int.
Variables: X
[tex]\int[/tex] [tex]\frac{5}{3e^x -2}[/tex]
None
U=3ex-2
DU=3ex
5[tex]\int[/tex][tex]\frac{1+3e^x -3e^x}{3e^x -2}[/tex]
5[tex]\int[/tex][tex]\frac{1+3e^x}{3e^x -2}[/tex] - 5[tex]\int[/tex][tex]\frac{DU}{U}[/tex]
Then I can't Integrate the first fraction.
Then tried conjugate:
5[tex]\int[/tex][tex]\frac{9e^{2x} -3e^x -2}{9e^{2x} -4}[/tex]
Here the den. is similar to the ArcTrig integrals, however the signs are wrong and there is no sq.rt.
Homework Statement
Find indefinite integral:
Variables (X)
Problem:
[tex]\int[/tex]Csc2(eCot(X))DX
Homework Equations
None:
The Attempt at a Solution
U=eCot(X)
DU=eCot(X) * -Csc2(X)
Pyth Iden Csc2(X)=1 + Tan2(X)
I keep going back to:
[tex]\int[/tex][Csc2(Something)]=-Cot(Something) I just can't figure out the relation.
Homework Statement
Find indef. Int.
Variables: X
[tex]\int[/tex] [tex]\frac{5}{3e^x -2}[/tex]
Homework Equations
None
The Attempt at a Solution
U=3ex-2
DU=3ex
5[tex]\int[/tex][tex]\frac{1+3e^x -3e^x}{3e^x -2}[/tex]
5[tex]\int[/tex][tex]\frac{1+3e^x}{3e^x -2}[/tex] - 5[tex]\int[/tex][tex]\frac{DU}{U}[/tex]
Then I can't Integrate the first fraction.
Then tried conjugate:
5[tex]\int[/tex][tex]\frac{9e^{2x} -3e^x -2}{9e^{2x} -4}[/tex]
Here the den. is similar to the ArcTrig integrals, however the signs are wrong and there is no sq.rt.
Last edited: