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Two narrow slits of widthaare separated by center-to-center distanced. Suppose that the ratio ofdtoais an integerd/a=m.

Show that in the diffraction patterns produced by this arrangement of slits, the mth interference maximum (corresponding to dsin(theta)=m[tex]\lambda[/tex]) is suppressed because of coincidence with a diffraction minimum. Show that this is also true for the 2mth, 3mth, etc., interference maxima.

My attemptdsin(theta)=m[tex]\lambda[/tex] indicates the conditions for interference maxima, where d is the distance between the two slits. We know that diffraction minimum occurs whena*sin(theta)=[tex]\lambda[/tex], where a is the slit width. Divide by both equations and we can determine which interference maximum coincides with the first diffraction minimum: d/a=m

I don't really understand what the question wants. Could someone please help me out? Thanks in advance.

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# Homework Help: PlEASE HELP: Diffraction by a single slit

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