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Two thin long charged metal plates are placed at x = 0, and x = d (that means they are plaed vertically, parallel to the Y Axis. Thus the distance between them is d. Assume that V(x=0) = 0, and that the thickness of the plates is lesser than d.
a) Find E(x) and V(x) when 0 < x < d.
First of all let the surface charge density [tex] \sigma = \frac{Q}{A} [/tex]
If i use Gauss Law then the Electric field [tex] E = \frac{\sigma}{\epsilon_{0}} [/tex] since the plates are conducting surfaces.
To find [tex] V(x) = \int E \cdot dx = \frac{\sigma}{\epsilon_{0}} \cdot dx = \frac{\sigma}{\epsilon_{0}} x [/tex]
i'm not really sure if i derived that expression correctly for V(x) which i why i need your help, please.
b) Find E(x) and V(x) if x > d
E(x>d) = zero or kq / (x+d)^2
V(x>d) = zero as well? or simply integrate E over x??
c) Find E(x) and V(x) if x<d
same as the previous one?? i.e. both E and V are zero?? Not realy sure here either?
d) Sketch E(x) and V(X)
I m not really sure about my expressions in a so if i found those out properly, with your help i can easily do this one!
Thank you in advance for your help!!
a) Find E(x) and V(x) when 0 < x < d.
First of all let the surface charge density [tex] \sigma = \frac{Q}{A} [/tex]
If i use Gauss Law then the Electric field [tex] E = \frac{\sigma}{\epsilon_{0}} [/tex] since the plates are conducting surfaces.
To find [tex] V(x) = \int E \cdot dx = \frac{\sigma}{\epsilon_{0}} \cdot dx = \frac{\sigma}{\epsilon_{0}} x [/tex]
i'm not really sure if i derived that expression correctly for V(x) which i why i need your help, please.
b) Find E(x) and V(x) if x > d
E(x>d) = zero or kq / (x+d)^2
V(x>d) = zero as well? or simply integrate E over x??
c) Find E(x) and V(x) if x<d
same as the previous one?? i.e. both E and V are zero?? Not realy sure here either?
d) Sketch E(x) and V(X)
I m not really sure about my expressions in a so if i found those out properly, with your help i can easily do this one!
Thank you in advance for your help!!
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