- #1

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I have:

KE = U

1/2*m*v^2 = 1/2ksX^s

My question is, how do I use the amplitude for this equation to work?? thanks! :-)

- Thread starter quickclick330
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- #1

- 83

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I have:

KE = U

1/2*m*v^2 = 1/2ksX^s

My question is, how do I use the amplitude for this equation to work?? thanks! :-)

- #2

Doc Al

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Hint: The total energy at __any__ point equals the sum of KE + PE.

- #3

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- #4

Doc Al

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What's the total energy expressed in terms of the amplitude?

- #5

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= 1/2ksX^2 + 1/2mv^2

when the amplitude = 4, then velocity = 0?

= 1/2*ks4^2 + 0

E = 8ks ?

- #6

Doc Al

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E = 1/2kA^2.

So, at the point where KE = PE, how much are each in terms of the total energy?

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- #8

Doc Al

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- #9

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and PE =KE

so that means that TE has to equal 2*PE

E = 2(1/2kA^2)

is this right?

- #10

Doc Al

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Yes!Since total energy = PE + KE

and PE =KE

so that means that TE has to equal 2*PE

Almost. The left side (E) is the total energy, so plug in the total energy in terms of A. On the right hand side, write the PE in terms of X. (Then just solve for X.)E = 2(1/2kA^2)

- #11

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ahh. that makes sense. thanks for your help!

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