One end of a massless spring is fixed and the other end is attatched to a mass. The mass slides on a horizontal frictionless table. The spring is parallel to the table. The mass-spring system oscillates with an amplitude of 4 cm. What is the magnitude of stretch of the spring when the kinetic energy of the mass is equal to the spring potential energy at that instant? (The spring ptotential is defined to be zero when at its relaxed length.)(adsbygoogle = window.adsbygoogle || []).push({});

I have:

KE = U

1/2*m*v^2 = 1/2ksX^s

My question is, how do I use the amplitude for this equation to work?? thanks! :-)

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# Homework Help: Please help->exam tonight! Spring Question

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