• Support PF! Buy your school textbooks, materials and every day products Here!

Please help, Express kinetic energy in terms of m and p?

  • Thread starter belleamie
  • Start date
  • #1
24
0
Hi, I think my brain froze and i'm not seeing it
the problem is

the momentum is defined as
p=mv=m(dx/dt)
express the kinetic energy in terms of m and p

~ Now I know kinetic = T= (1/2)mv^2
and that P=mv
I figured that it must be t= (1/2)p^2
till i realized that I'm missing in terms of m. I just got stumped
 

Answers and Replies

  • #2
T= (1/2)p^2

You know p=mv, so p^2 gives (mv)^2

T=/= (1/2)(mv)^2

where =/= represents 'is not equal to'

I suspect that you will kick yourself when it dawns on you.
 
  • #3
48
0
p=mv -> v=p/m

T=1/2*m*v^2

T=1/2*m(p/m)^2 -> T=1/2((p^2)/m)
 

Related Threads for: Please help, Express kinetic energy in terms of m and p?

Replies
1
Views
3K
Replies
5
Views
10K
Replies
1
Views
956
Replies
5
Views
8K
Replies
3
Views
2K
Replies
3
Views
3K
Replies
6
Views
2K
Top