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Please help for relativistic doppler shift

  1. May 16, 2015 #1
    i need thee the derivation of relativistic doppler shift. i found its derivation in the book of Serway, but it is not in detail and step by step.
    in the book there is given that:

    can anyone give me the step after eq#1.13? how eq#1.13 converted in the form of eq#1.14?
  2. jcsd
  3. May 16, 2015 #2


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    Gold Member

    The step from 1.13 to 1.14 is just ## 1-\frac{v^2}{c^2}=(1- \frac{v}{c})(1+ \frac{v}{ c}) ##
  4. May 16, 2015 #3
    but how comes a square root in the denominator of eq#1.14
  5. May 16, 2015 #4
    thanks my problem solved
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