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mynameisfunk
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Homework Statement
I have a 3 parter. I think I have the first part, the second part I am not sure of and the third part I am kind of getting desperate with...
(a) Prove first that if c is a constant, and [tex]\lim_{n\rightarrow \inf} s_n = s[/tex] , then [tex]\lim_{n\rightarrow \inf} cs_n = cs[/tex].
(b) Prove that if [tex]\lim_{n\rightarrow \inf} s_n = s[/tex] then [tex]\lim_{n\rightarrow \inf} s^2_n = s^2[/tex]. (Hint:recall that convergent sequences are bounded.)
(c) Use the polarization identity [tex]ab = \frac{1}{4}((a+b)^2-(a-b)^2)[/tex] to prove that if [tex]\lim_{n\rightarrow \inf} s_n = s[/tex] and [tex]\lim_{n\rightarrow \inf} t_n = t[/tex] , then [tex]\lim_{n\rightarrow \inf} t_ns_n = ts[/tex].
Homework Equations
The Attempt at a Solution
(a) Since for all [tex]\varepsilon > 0[/tex] , there exists an [tex]N[/tex], such that if [tex]n > N , |s_n-s| < \varepsilon[/tex] , there should
exist an [tex]n_{\mu} \geq n[/tex] such that [tex]c|s_n-s| \leq \varepsilon[/tex] hence [tex]\lim_{n\rightarrow \inf} cs_n = cs[/tex]
(b) [tex]\lim_{n \rightarrow \inf}s_n = s[/tex] implies that [tex]{s_n}[/tex] is compact and bounded. Take [tex]\varepsilon > 0[/tex]. For some [tex]M[/tex], if [tex]n \geq M[/tex], then [tex]|s_n-s|=|s-s_n| < \sqrt{\varepsilon}[/tex] and therefore [tex]|s-s_n|^2 < \varepsilon[/tex]. so now [tex]\lim_{n \rightarrow \inf}(s_n-s)^2 = 0[/tex].
Take [tex]|s_n^2-s^2| = |s_n(s_n-s)-s(s-s_n)| \leq |s_n||s_n-s|-|s||s-s_n| \leq |s_n-s|(|s_n|-|s|) \leq \varepsilon[/tex] which gives us [tex]\lim_{n \rightarrow \inf}(s_n^2-s^2)=0[/tex]
(c) If my other two are even correct, this is where I am stuck. PLEASE give me a little nudge...
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