- #1

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I don't know where to begin...

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- Thread starter shann0nsHERE
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- #1

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I don't know where to begin...

- #2

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A thread holds a 1.5-kg and a 4.50-kg cart together. After the thread is burned, a compressed spring pushes the carts apart, giving the 1.5 kg cart a speed of 27 cm/s to the left. What is the velocity of the 4.5-kg cart?

I would be so grateful if someone could help me..

- #3

rl.bhat

Homework Helper

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Just go through the conservation of linear momentum.

- #4

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Also: I would start a new thread for each problem, else things get confusing/messy.

- #5

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ha thanks for the heads up, i just started this

Andd thank you both for the help

- #6

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ha thanks for the heads up, i just started this

Andd thank you both for the help

Okay, well paraphrasing Conservation of momentum says that if no external forces act on a system (which is true in this case), then the total linear momentum is conserved.

That is, [itex]\sum mv_{initial}=\sum mv_{final}[/itex]

In this case,

[tex]M_{bullet}V_{bullet}+M_{block}V_{block}=M_{(block+bullet)}V'_{(block+bullet)}[/tex]

where I used the ' symbol to indicate velocity after the collision

And Yes, they are both conservation of momentum.

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