Problem 1. A pelican has a fish in his mouth. He's traveling 3 m/s. He drops fish. What is fish's distance from pelican after 2 s? I did this Vi = 3m/s for both the fish and the pelican a = 9.8 (is this negative or pos?) Then i used x = Vi (T) 1/2 (a) (t) ^2 I got for this 25.6 m Did I do this right? If no, what i am doing wrong.. Problem 2. I am so confused on this. I have tried this for 65 minutes now. Here it is. A speeding car is traveling 92.0 km/h toward a police car at rest. facing the same direction as the speeding car. If the police car begins accelerating when the speeding car is 250.0 m behind the police car, what must the police car's acceleration be in order for the police car to reach the speeding car's velocity at the moment the speeding car catches up? Assume that the speed car does not slow down. Ok i have no clue how to do this one. I tried everything Can someone please give me detailed instructions on this one and tell me if my number 1 was correct? Sorry if this is a burden THis is my first post!