- #1

To0ta

- 6

- 0

f : E[tex]\rightarrowR[/tex]

1_1 , onto , contonuo

such that

f[tex]^{}-1[/tex] : f(E) [tex]\rightarrowR[/tex]

is not continows

Please help me in finding a solution

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter To0ta
- Start date

- #1

To0ta

- 6

- 0

f : E[tex]\rightarrowR[/tex]

1_1 , onto , contonuo

such that

f[tex]^{}-1[/tex] : f(E) [tex]\rightarrowR[/tex]

is not continows

Please help me in finding a solution

- #2

Mentallic

Homework Helper

- 3,802

- 94

Can you repost it such that it's more readable please?

- #3

rs1n

- 179

- 2

Let [itex]E\subseteq \mathbb{R}[/itex]. Find a function [itex]f : E\rightarrow \mathbb{R}[/itex] that is one-to-one, onto, and continuous such that [itex]f^{-1} : f(E) \rightarrow \mathbb{R}[/itex] is not continuous.

Is this your question?

- #4

To0ta

- 6

- 0

Yes, this is my question

- #5

Gregg

- 459

- 0

what about e^x?

- #6

Mark44

Mentor

- 36,332

- 8,293

Yes, this is my question

Why don't you just type your question? All of the stuff you are doing with special fonts, centering, and font size is distracting.

Share:

- Replies
- 2

- Views
- 163

- Replies
- 3

- Views
- 382

- Replies
- 13

- Views
- 935

- Replies
- 17

- Views
- 680

- Last Post

- Replies
- 8

- Views
- 581

- Replies
- 2

- Views
- 574

- Replies
- 4

- Views
- 789

- Replies
- 6

- Views
- 773

- Replies
- 10

- Views
- 1K

- Replies
- 5

- Views
- 157