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Abhishekdas

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**Please help me out with this question on torque....**

## Homework Statement

A cylinder of mass M and radius R is resting on a horizontal platform(which is parallel to the x-y plane) with its axis fixed along the y -axis and free to rotate about its axis. The platform is given a motion in the x-direction given by x=Acos(wt). There is no slipping between the cylinder and platform.

Find The maximum torque acting on the cylinder during its motion?

## Homework Equations

d

^{2}x/dt

^{2}=a

for no slipping a=R(alpha) alpha is dw/dt....

## The Attempt at a Solution

I found maximum acceleration of platform and equated it as R times alpha.....

found alpha from there and then used torque = I*alpha

So max acceleration of platform is (neglecting sign) Aw

^{2}

alpha=Aw

^{2}/R

I=mR

^{2}/2

You get torque as =MRAw

^{2}/2

Answer is MRAw

^{2}/3

please reply....thank you.....

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