- #1
physics noob
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A 20 g bullet is fired horizontally into a .5 kg wooden block, resting on a horizontal surface ( kinetic friction coefficient is .2), THe bullet goes through the block and comes out the other side with a speed of 200m/s... if the block travels 1 m before coming to rest, what was the Vi of the bullet... (ignore work of gravity on the bullet...ps, this is a momentum problem i think, i just can't get it, i would GREATLY appreciate any help on this... i have the answer but i need to work to get credit... this is what i have so far
i tried using Wnet = change in KE
Fx - .2(.52)(1m)(9.8) = x - 1.02 J but i have no idea what to do next, i think it is a perfectly inelastic collision during the one meter, but than the bullet come out!?! how the heck do you account for that? again any help is appriaciated,,, thanks for y our time
i tried using Wnet = change in KE
Fx - .2(.52)(1m)(9.8) = x - 1.02 J but i have no idea what to do next, i think it is a perfectly inelastic collision during the one meter, but than the bullet come out!?! how the heck do you account for that? again any help is appriaciated,,, thanks for y our time