1. Dec 7, 2008

Hamid1

Hi all,
can anybody complete my answer?(I'm unable to solve the second part of the integral)

thanks and excuse me for english;)

Last edited by a moderator: Apr 24, 2017
2. Dec 7, 2008

tiny-tim

Welcome to PF!

Last edited by a moderator: Apr 24, 2017
3. Dec 8, 2008

Hamid1

Thank you,
ermmm...your very first line is incorrect: your basically claiming that $(2x+6)-6=1$ which is clearly false.
Try a u-substitution of the form $u=x+3$ instead.