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Please help me with this

  • Thread starter Britney2
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  • #1
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A charged particle that moves with the speed v=8x10(7) goes in a magnetic field where B=0.7 T (B is the induction) and it makes an angle λ=45◦ with force lines. How is the specific charge(q/m) if the radius is R=4 cm?
(qvb=mv2/R qvb is the formula of the Lorenc force and mv2/R is the centripetal.)
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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The force exerted on the charged particle at an angle [itex]\theta[/itex] to a magnetic field of flux density,B, and moving with a velocity,v, provides the centripetal force to keep it moving a circular path.

So that

[tex]BQvsin\theta=\frac{mv^2}{r}[/tex]

Which is the formula you posted in a sense....
 

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