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Please, help me

  1. Dec 20, 2009 #1
    1. The problem statement, all variables and given/known data


    1-adding the same amount of heat to two samples does not produce the same increase in temperature. What physical parameters of hte bodies might be different?

    2-We have a sample of metal with mass m. We supply an amount of heat Q and the temperature rises by deltaT.

    (a) Write down the heat capacity of the sample in terms of m, Q and delta×T.

    We increase the amount of heat supplied to the sample to 3Q

    (b) What is the change in temperature?

    (c)By what amount should we change the mass of the sample for the increase in temperature to be 10 deltaT?

    3-We are going to increase the temperature of a sample of aluminium with mass 0.50kg. The initial temperature of the sampleis 300K. The final temperature is 400K. How much heat is required?

    2. Relevant equations

    1- (Hint: Q=m×c×deltaT)

    3-(specific heat capacity of aluminium is 897 JKg^(-1)K^(-1)

    3. The attempt at a solution

    I don't know if the answers are correct or not

    A1:The atoms. may be the first body is sold and the second bdy is liquid


    (a) Q=m×deltaT

    If we increase it to 3Q

    ==> 3Q=m×c×deltaT ==> Q=(m×deltaT)/3

    (b) The change in temperature is deltaT = T2 - T1

    (c) for this there is no attempt



    ==> 0.50 × 897 × (400 - 300 ) = 44850


    Please, please , please , and please i hope you to tell me what is the correct answer

    i am trying allways to be a good student in physics but usually i don't answer quistions correctly.

    please i hope you to teach me.

    I will say thanx for you to the end of my life :smile:

  2. jcsd
  3. Dec 21, 2009 #2


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    Homework Helper

    You have written a hint: Q = m*c*ΔT.
    In the problem Q and ΔT remain constant. Then which quarantines should be different for the two bodies?
  4. Dec 24, 2009 #3
    First: thanx for your help


    The quarantines should be different for the two bodies are (c=heat capacity ,and m=mass of substance)

    Is my answer right or not?

    thanx again for your help:smile:
  5. Dec 24, 2009 #4


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    Homework Helper

    Your answer is correct.
  6. Dec 24, 2009 #5

    Thank you

    please:shy:, let's answer the remaining questions :redface: if you don't mind
  7. Dec 27, 2009 #6


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    Staff Emeritus
    Science Advisor
    Homework Helper

    No, Q=m×c×deltaT as stated in the hint. Therefore c=____?

    This goes with part (b), not (a).
    You are not understanding what is being asked.
    The temperature change is deltaT when the amount of heat supplied is Q. If, instead, an amount of heat 3Q is added, what is the temperature change then?
    This looks correct.
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