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Please help, thermodinamics exercise.

  1. Apr 9, 2007 #1
    I tried but I cannot do it. Please help.

    Two rigid adiabatic containers have inside the same ideal gas, respectively N1=3mol at a temperature T1=340K and N2=2mol at a temperature T2=280K. The two containers come into contact by opening a faucet, and the gas mixes, getting to a temperature T3.


    1) the variation of the total internal energy of the gas.
    2) the value of the final temperature T3.

    I really need a hand, if you don't want to solve it please tell me how to do it. Any help is truly appreciated. Pardon the probably incorrect use of words, I'm not english.
  2. jcsd
  3. Apr 9, 2007 #2
    Here, I think the total internal energy will remain constant. Since U=nf RT/2, you can use that to find the internal energy of the gas in both the parts and add it up to find the final internal energy which will have n1+n2 moles of the gas.
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