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Please Help to solve a problem

  1. Sep 21, 2008 #1
    Calculate the following quantity:
    Volume of 0.98 M calcium chloride (mL) that must be diluted with water to prepare 341 mL of a 0.23 M chloride ion solution.
     
  2. jcsd
  3. Sep 21, 2008 #2

    Borek

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    Staff: Mentor

    You have to try first.
     
  4. Sep 21, 2008 #3
    If I understand the problem correctly, I should find how many mol of chloride ions is produced by one mol of calcium chloride first. DO you think that is right?
     
  5. Sep 21, 2008 #4

    Borek

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    Staff: Mentor

    That's possible approach. For sure you have to do it at some stage.
     
  6. Sep 21, 2008 #5
    This is how i worked it out:
    CaCl2 + 2H2O => Ca(OH)2 + 2HCl

    Mol of Cl:
    341mL * (1L/1000mL) * 0.23 mol/L= 0.078 mol of Cl

    Vol. of CaCl2:
    0.078 mol Cl * (1mol CaCl2/2mol Cl) * (1L/0.98 mol CaCl2) * (1000mL/1L) = 40.0 mL CaCl2

    I TRIED HARD ON THIS... IS THIS THE RIGHT ANNSWER!
     
  7. Sep 21, 2008 #6

    Borek

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    Staff: Mentor

    Looks OK.
     
  8. Sep 21, 2008 #7
    Really!? Thanks.

    By the way. I think I post this in the wrong section. If you can, please move this post to the proper section. I will read the regulations and follow them the next times.
     
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