- #1

- 11

- 0

So I know the equation:

I

_{trans}= I

_{0}Cos

^{2}θ

Since this light starts out as polarized, there is no need to cut it in half like you do for unpolarized light. So I did the equation through the first polzarizer, using 30 degree as my angle, and came out with I=0.75

Now I used that 0.75 as my new I

_{0}as the light went through the 2nd polarizer, this time I used 60 degrees as my θ and I got 0.1875, which would be B.

However, I saw the same problem elsewhere where the guy got D) as the answer because he used 30 for θ instead of 60.