1. Sep 20, 2013

rxfudd

I cannot figure out where I am going wrong. My answer and the textbook answer are different by a negative sign. Can someone review my work and tell me what I am doing wrong?

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2. Sep 20, 2013

vanhees71

Why do you think, your solution is wrong? It's perfectly right! It's the general solution of the equation (I've not checked it, but this you can do by taking the derivative and check whether it fulfills your equation), and whether you call the integration constant $-C_3$ or $C$ doesn't matter.

The solution is made unique by giving, e.g., an initial value $y(0)=y_0$ as a constraint. If you use this in your and the textbook's answer you'll get the same result by choosing the right $C_3$ and $C$ to match the initial-value constraint, respectively.

3. Sep 20, 2013

rxfudd

Ah yes, the constant...the (x2+4)-4 term can be positive or negative because of the constant.

Thank you for reviewing my work and pointing that out. Amateur mistake :)