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Please helpe me

  • Thread starter abdooo89
  • Start date
  • #1
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i have two problem

1- (-3x+2y)dy=(x-2y)dx


2- y*dy= - (y+cos x ) dx

pleeeeeeeeeeeeeeeeeeeeeezzzzzzzzzz help me quiqly:frown:
 

Answers and Replies

  • #2
SammyS
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What have you tried?

Where are you stuck?
 
  • #3
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i can not seprate the variables
 
  • #4
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if posible plese solve it for me
 
  • #5
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also when i seprat the viaribles big proplem for integration
 
  • #6
LCKurtz
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For the first one try y = ux, dy = udx + xdu.
 
  • #7
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i try but integration is deficlult
 
  • #8
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pleas help
 
  • #9
LCKurtz
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For the first one try y = ux, dy = udx + xdu.
i try but integration is deficlult
pleas help
You need to show us what you have done so we can see where you are having a problem.
 
  • #10
SammyS
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i try but integration is deficlult
At least, show what you have.

You asked for help, show what efforts you have made.
 
  • #11
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:frown: how u can take integration for both side
 
  • #12
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x2 dx2+(x2+ cos x1 ) dx1=0 take integration plese help
 
  • #13
Math Is Hard
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Note: moved to Homework and Coursework Questions forum where this should have been posted.
 
  • #14
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if posible plese solve it for me
That is strictly against the forum's policy, part of which is shown below.

https://www.physicsforums.com/showthread.php?t=414380
Homework Help:
NOTE: You MUST show that you have attempted to answer your question in order to receive help. You MUST make use of the homework template, which automatically appears when a new topic is created in the homework help forums. Once your question or problem has been responded to, do not go back and delete (or edit) your original post.

On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made.
 

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