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kevinf
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please... need urgent help about vectors
in the sum vector a + vector b = vector c, vector a has a magnitude of 12.0m and is angled 40.0 degrees counterclockwise from the +x direction, and vector c has a magnitude of 15.0m and is angled 20.0 degrees counterclockwise from the -x direction
a)what is the magnitude
b) what is the angle (relative to +x) of vector B.
i first found the x and y component of each vector:
so for vector a the x component would be 12 cos(40) and the y component would be 12 sin(40). for vector C the x component would be 15 cos (20) and the y component would be 15 sin (40). so do i just add the x components of the 2 vectors and the y component of the 2 vectors, do pythagorean theorem and find out what the magnitude is.
so would i be (12cos(40)*15cos(20))^2+(12sin(40)+15sin(20))^2 and then square root?
Homework Statement
in the sum vector a + vector b = vector c, vector a has a magnitude of 12.0m and is angled 40.0 degrees counterclockwise from the +x direction, and vector c has a magnitude of 15.0m and is angled 20.0 degrees counterclockwise from the -x direction
a)what is the magnitude
b) what is the angle (relative to +x) of vector B.
The Attempt at a Solution
i first found the x and y component of each vector:
so for vector a the x component would be 12 cos(40) and the y component would be 12 sin(40). for vector C the x component would be 15 cos (20) and the y component would be 15 sin (40). so do i just add the x components of the 2 vectors and the y component of the 2 vectors, do pythagorean theorem and find out what the magnitude is.
so would i be (12cos(40)*15cos(20))^2+(12sin(40)+15sin(20))^2 and then square root?
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