1. The problem statement, all variables and given/known data Using the local minima, local maxima and points of inflection of the following function, plot the graph: f(x) = 9x4-11x3+3x2+1 3. The attempt at a solution f(x) = 9x4-11x3+3x2+1 f ' (x) = 36x3-33x2+6x = 3x(12x2-11x+2) = 3x(3x-2)(4x-1) therefore we have x = 0, 2/3, 1/4 now, finding the second derivative of the function we have: f '' (x) = 108x2 - 66x + 6 plugging in our values of x into this, we have: f '' (0) = 6 f '' (2/3) = 10 f '' (1/4) = - 15/4 therefore we have local minima x = 0, 2/3 and local maxima x = 1/4 I have also found 1 point of inflection to be: 0.029... I have plotted the function using an online function plotter, and the local minima/maxima dont appear to correspond with the actual graph. Could someone please show in which step i went wrong?