(adsbygoogle = window.adsbygoogle || []).push({}); The problem statement.

Suppose x''(t) = 1 for [tex]1\leq(t)\leq2[/tex], and x''(t) = 0 for all other (t)

(a) Plot x''(t) for [tex]0\leq(t)\leq3[/tex]

(b) Plot x'(t) for [tex]0\leq(t)\leq3[/tex]. Assume x'(0) = 0

(c) Plot x(t) for [tex]0\leq(t)\leq3[/tex]. Assume x(0) = 0

The attempt at a solution

I assumed 'x' being the vertical axis and 't' being the horizontal axis.

For (a) I know that there are going to be two points at 1 and two points at 0.

My main question is when I graph these plots should I treat points 0 and 3 on the t-axis as discontinuities, and just put a point of where they're at and not include them when connecting the non-zero points, or should I connect all the points together, despite the discontinuity?

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# Homework Help: Plotting Derivatives

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