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Plotting Straight Line Graphs

  1. Jun 15, 2013 #1
    So, I have to assess the relationship between the Constant of a Spring and the Time Period of Oscillations.

    I have researched the equation that links the two and I know that to have a straight line graph I need to plot:

    T2 against 1/K

    However, I do not know why; how I get to that conclusion.

    I have read about log-log graphs and played around with the concept to see if it would yield the plot I mentioned above. I tried plotting for the log of T against the log of K and I did get a straight line plot. I checked if my gradient was equal to -0.5 and my y-intercept was equal to (log 2∏-0.5 log m) and they were, but I still do not understand why I have to plot T2 against 1/K.

    Can anyone please shed some light onto this please?

    Thanks in advance!
     
  2. jcsd
  3. Jun 15, 2013 #2

    rock.freak667

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    Homework Helper

    You are asked to plot that because of the derivation of the periodic time formula for a spring oscillation.

    The final equation is

    [tex]T = 2 \pi \sqrt{\frac{m}{k}}[/tex]

    If you square both sides you will get


    [tex]T^2 = \frac{4 \pi ^2 m}{k}[/tex]

    Which is the form Y=MX where Y = T2 and X = 1/k.

    Thus plotting Y vs X i.e. T2 vs. 1/k will give you a straight line. So you can get the mass oscillating if you desire from the gradient of the graph you plotted.
     
  4. Jun 15, 2013 #3
    I like your idea of using a log-log plot much better. I have over 40 years of experience as a practicing engineer, and that is the way I would do it. Congratulations on thinking out of the box.

    Chet
     
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