Plotting Total Power for R=2 Ohms - V1,V2 Range 0-20V, Va = 0

In summary: This will give you the values of V1 and V2 that produce Va = 0 while minimizing the total power absorbed by the resistors. In summary, for R = 2 ohms, plot Va as a function of V1 and V2 between 0 and 20 volts, and then find the values of V1 and V2 that minimize the total power absorbed by the resistors.
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For R=2 ohms plot Va as a function of V1 and V2. For V1 and V2 are between 0 and 20 volts. Second part is to find the values of V1 and V2 that produce Va = 0 while minimizing the total power absorbed by the resistors (hint you may want a second plot of total power as a function of V1 and V2).

R = 2 ohms
V1 = 0:1:20
V2 = 0:1:20
Va = in terms of V1 and V2/=0
KCL at supernode


DP42.jpg


As you can see I've already solved the first part. and here is the equations or KCL being applied at the supernode. I've also set Va equal to zero and solved getting 16 = V1 - V2. Now I'm at a loss as to how to proceed. The plotting part in Matlab is easy but I'm unsure how what the second part is even really asking. Any help would be greatly appreciated.
 
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  • #2
The second part is asking you to find the values of V1 and V2 that minimize the total power absorbed by the resistors. To do this, you need to calculate the total power for each combination of V1 and V2. The total power is given by the equation P = (V1^2 + V2^2)/R, where R is the resistance of the resistors. You can then create a plot of total power as a function of V1 and V2 and find the combination of V1 and V2 that minimizes the total power.
 
  • #3


For the second part, you are essentially trying to find the combination of V1 and V2 that will result in Va = 0 while minimizing the total power absorbed by the resistors. This can be achieved by finding the minimum value of the total power function as a function of V1 and V2.

To do this, you can use the equations you have already derived for KCL at the supernode and set Va = 0. This will give you a relation between V1 and V2, which can be used to eliminate one variable in the total power function. Then, you can take the derivative of the total power function with respect to the remaining variable and set it equal to 0 to find the minimum value.

Once you have the minimum value, you can plug it back into the equation for Va and solve for the corresponding values of V1 and V2. These values will produce Va = 0 and minimize the total power absorbed by the resistors.

In terms of plotting this in Matlab, you can use the "fminsearch" function to find the minimum value of the total power function and then use the corresponding values of V1 and V2 to plot the total power function as a function of V1 and V2. This will show the minimum power value on the plot and the corresponding values of V1 and V2 that achieve it.
 

What is the purpose of plotting total power for R=2 Ohms?

The purpose of plotting total power for R=2 Ohms is to visualize the relationship between voltage and power in a circuit with a resistance of 2 Ohms. This can help to analyze the efficiency of the circuit and determine the optimal voltage range for maximum power output.

What is the significance of the V1,V2 range being 0-20V?

The V1,V2 range of 0-20V represents the voltage range that will be tested in the circuit. This range was likely chosen to cover a wide range of potential voltages and provide a comprehensive understanding of the power output at different voltage levels.

Why is Va set to 0 in this experiment?

Va, or the applied voltage, is set to 0 in this experiment to isolate the effects of the independent variables (V1 and V2) on the circuit's power output. By holding Va constant, any changes in power can be attributed solely to changes in V1 and V2.

What is the expected shape of the graph for this experiment?

The expected shape of the graph for this experiment is a parabola, with the maximum power output occurring at the vertex. This is because power is directly proportional to voltage squared (P=V^2/R), so as voltage increases, power initially increases, but eventually reaches a maximum and then decreases.

How can this experiment be useful in practical applications?

This experiment can be useful in practical applications, such as designing and optimizing circuits, as it provides insight into the relationship between voltage and power. It can also help to identify any potential issues or inefficiencies in a circuit and inform decisions on voltage levels for maximum power output.

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