1. The problem statement, all variables and given/known data A 0.30 kg puck A, initially at rest on a frictionless horizontal surface, is struck by a 0.20 kg puck B that is initially moving along the x-axis with a velocity of 2.0 m/s. After the collision, the 0.20 kg puck has a speed of 1.0 m/s at an angle of θ = 530 to the positive x-axis. a) Determine the velocity of the 0.30 kg puck after the collision. 2. Relevant equations total mommentum before collision + total momentum after collision 3. The attempt at a solution total momentum before collision in x puck A 0.2 x 2 = 0.4 puck B 0.3 x 0 total = 0.7kgm/s total momentum before collision in y = 0 for all Total momentum after collision x puck A 0.2 x 1 x cos 53=0.12 puck B 0.3 x V x cos 53 Total =0.7kgm/s Total momentum after collision y puck A 0.2 x 1 sin 53 = 0.1597 puck B 0.3 x V x sin53 Total =0 Resolve in x for puck B 0.3 x V x cos 53 Let Vcos 53 = Vx 0.3 x Vx + 0.12 = 0.7 Vx = 1.93333m/s Resolve in y for puck B 0.3 x V x sin 53 Let Vsin 53 = Vy 0.3 x Vy + 0.1597 = 0 Vy = -0.53 V2=Vx2 + Vy2 V2 = 1.933332+(-0.53)2 V=√4.02 v=2.005m/s Is this right???